The circuit described here can be used to ensure that a 12 V sealed lead acid (SLA) gel battery isn’t discharged too deeply. The principal part of the circuit is a bistable relay, which is driven by the output of an op amp.
The battery voltage is first
reduced via D1, R1, P1 and R2, and then continuously compared with a
reference voltage set up by diode D2. When the battery discharges too
much and its terminal voltage drops below the level set by P1, the
output of the opamp becomes High, which causes the relay to toggle.
This in turn isolates the load from the battery. The battery can be
reconnected via S1 once the battery has been replaced or recharged.
The
relay used in the prototype is a 5 V bistable type made by Omron
(G6AK-234P-ST-US 5 VDC). The two windings of the relay each have a
resistance of 139 Ω (for the RAL-D 5 W-K made by Fujitsu this is 167
Ω). When the battery voltage starts to become too low and the relay is
being reset the current consumption of the circuit is about 45 mA.
Shortly after the load has been disconnected, when the battery voltage
rises above the reference voltage again, the reset coil will no longer
be powered and the current consumption drops back to about 2.5 mA.
Lead Acid Battery Protector Circuit Diagram
The range of P1 has intentionally been kept small. With a reference voltage of 5.6 V (D2) and a voltage drop of 0.64 V across D1, the circuit reacts within a voltage span of 11.5 V and 11.8 V. This range is obviously dependent on the zener diode used and the tolerance.
For a greater span you can use a larger value for P1 without any problems. With the potentiometer at its mid setting the circuit switches at about 11.6 V.
Author : Jürgen Stannieder
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